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P70.cpp
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140 lines (135 loc) · 2.87 KB
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#include<iostream>
#include<fstream>
#include<string>
#include<queue>
#include<stack>
#include<vector>
#include<map>
#include<set>
#include<list>
#include<algorithm>
#include<math.h>
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<cmath>
#include<ctime>
#include<iomanip>
#define MAXN 10000000
#define LL long long
#define eps 1e-6
#define inf 0x3f3f3f3f
using namespace std;
int prime[MAXN], Phi[MAXN] = {0, 1};
bool comp[MAXN];
int digit1[10], digit2[10];
void getprime()
{
for(int p = 2; p < MAXN; p++)
{
if(!comp[p])
{
for(int i = p + p; i < MAXN; i += p)
comp[i] = true;
prime[++prime[0]] = p;
}
}
return;
}
int Totient(int n)
{
if(!comp[n])
Phi[n] = n - 1;
else if(0 == Phi[n])
{
int m = 1, i = 1, k = n;
while(n % prime[i])
i++;
while(0 == k % prime[i])
{
m *= prime[i];
k /= prime[i];
}
Phi[n] = Phi[m] * Phi[k];//m * k == n
// The totient function is a multiplicative function
//if two numbers m and n are relatively prime, then φ(mn) = φ(m)φ(n).
}
//φ(n^k) = n^(k - 1)φ(n) = n * φ(n^(k - 1))
for(LL t = (LL)n * n; t < MAXN; t *= n)
Phi[t] = n * Phi[t / n];
return Phi[n];
}
/*A faster way
类似于扫描法求质数
for(int i = 1; i <= MAXN; i++)
Phi[i] = i;
for(int i = 2; i <= MAXN; i++)
{
if(Phi[i] == i)
{
for(int j = i;j <= MAXN; j += i)
Phi[j] = Phi[j] / i * (i - 1);
}
}
*/
bool isPerm(int phi, int n)
{
memset(digit1, 0, sizeof(digit1));
memset(digit2, 0, sizeof(digit2));
while(phi)
{
digit1[phi % 10]++;
phi /= 10;
}
while(n)
{
digit2[n % 10]++;
n /= 10;
}
for(int i = 0; i <= 9; i++)
if(digit1[i] != digit2[i])
return false;
return true;
}
int main()
{
double duration;
clock_t start = clock();
getprime();
double Min = MAXN, temp;
int rec, T;
for(int i = 2; i < MAXN; i++)
{
T = Totient(i);
if(isPerm(T, i))
{
temp = (double)i / T;
if(Min > temp + eps)
{
Min = temp;
rec = i;
//printf("%d %lf\n", rec, Min);
}
}
}
printf("%d\n", rec);
duration = (double)(clock() - start) / CLOCKS_PER_SEC;
printf("time cost: %lf s\n", duration);
return 0;
}
/*
for(int i = 1; i <= MAXN; i++)
Totient[i] = i;
for(int i = 2; i <= MAXN; i++)
{
if(Totient[i] == i)
{
for(int j = i;j <= MAXN; j += i)
Totient[j] = Totient[j] / i * (i - 1);
}
}
LL ans=0LL;
for(int i = 2;i <= MAXN; i++)
ans+=Totient[i];
printf("%I64d\n", ans);
*/