Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.
For example, given the following triangle
[
[2],
[3,4],
[6,5,7],
[4,1,8,3]
]
The minimum path sum from top to bottom is 11 (i.e., 2 + 3 + 5 + 1 = 11).
Note:
Bonus point if you are able to do this using only O(n) extra space, where n is the total number of rows in the triangle.
public class Solution {
public int minimumTotal(List<List<Integer>> triangle) {
if (triangle.size() == 0) {
return 0;
}
int length = triangle.size();
for (int i = length - 2; i >= 0; i--) {
List<Integer> curLevel = triangle.get(i);
for (int j = curLevel.size()-1; j >= 0; j--) {
curLevel.set(
j,
curLevel.get(j)
+ Math.min(triangle.get(i + 1).get(j), triangle
.get(i + 1).get(j + 1)));
}
}
return triangle.get(0).get(0);
}
}