Please describe your feature request.
That the ApiError for status code "forbidden" ("You aren't permitted to perform this request.") have its own exception class inheriting from ApiError so that it can be caught separately more easily.
Describe your solution.
I would suggest that there be a new exception class created that inherits from ApiError that is raised when ApiError is encountered with status code forbidden. Below is a rough somewhat pseudocode of what that could potentially look like, at least as quick way to add this in/illustrate.
class ApiError(HTTPError):
def __new__(cls, message, error_type=None):
if error_type == 'forbidden':
return super().__new__(ForbiddenError)
return super().__new__(cls)
class ForbiddenError(ApiError):
passDescribe alternatives you have considered.
You could catch it through ApiError and handle via checking e.error_code == "forbidden", but it is somewhat cleaner to handle as a different exception type in my opinion.
Additional context
No response
Please describe your feature request.
That the ApiError for status code "forbidden" ("You aren't permitted to perform this request.") have its own exception class inheriting from ApiError so that it can be caught separately more easily.
Describe your solution.
I would suggest that there be a new exception class created that inherits from ApiError that is raised when ApiError is encountered with status code forbidden. Below is a rough somewhat pseudocode of what that could potentially look like, at least as quick way to add this in/illustrate.
Describe alternatives you have considered.
You could catch it through ApiError and handle via checking
e.error_code == "forbidden", but it is somewhat cleaner to handle as a different exception type in my opinion.Additional context
No response