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A_Design_Tutorial_Learn_from_Math.cpp
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191 lines (175 loc) · 3.73 KB
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#include <bits/stdc++.h>
#include <algorithm>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization("unroll-loops")
#define pb push_back
#define nl '\n'
#define sp ' '
#define pi 2 * acos(0.0)
#define mod 1000000007
// Types of declarations /////////////////////////////////
#define all(x) x.begin(), x.end()
using ll = long long;
using vb = vector<bool>;
using vvb = vector<vb>;
using vi = vector<int>;
using vvi = vector<vi>;
using vl = vector<ll>;
using vvl = vector<vl>;
using vc = vector<char>;
using vvc = vector<vc>;
using vs = vector<string>;
// Odd Even /////////////////////////////////////////////
bool odd(ll num) { return ((num & 1) == 1); }
bool even(ll num) { return ((num & 1) == 0); }
// Mint
const ll MOD = 998244353;
struct Mint
{
ll v;
Mint(ll _v = 0)
{
v = _v % MOD;
if (v < 0)
v += MOD;
}
Mint operator+(const Mint &o) const { return Mint(v + o.v); }
Mint operator-(const Mint &o) const { return Mint(v - o.v); }
Mint operator*(const Mint &o) const { return Mint(v * o.v); }
Mint &operator+=(const Mint &o)
{
v += o.v;
if (v >= MOD)
v -= MOD;
return *this;
}
Mint &operator-=(const Mint &o)
{
v -= o.v;
if (v < 0)
v += MOD;
return *this;
}
Mint &operator*=(const Mint &o)
{
v = (v * o.v) % MOD;
return *this;
}
static Mint pow(Mint a, ll e)
{
Mint r(1);
while (e > 0)
{
if (e & 1)
r *= a;
a *= a;
e >>= 1;
}
return r;
}
Mint inv() const { return pow(*this, MOD - 2); }
Mint operator/(const Mint &o) const { return *this * o.inv(); }
Mint &operator/=(const Mint &o)
{
*this = *this / o;
return *this;
}
ll val() const { return v; }
};
//////////////////////////////////////////////////////// Prime
bool isPrime(int n)
{
for (int i = 2; i * i <= n; i++)
{
if (n % i == 0)
return false;
}
return true;
}
///////////////////////////////////////////////////////// LCM GCD
long long gcd(long long a, long long b)
{
while (b != 0)
{
long long temp = b;
b = a % b;
a = temp;
}
return a;
}
long long lcm(long long a, long long b)
{
return (a / gcd(a, b)) * b;
}
////////////////////////////////////////////////////////// SQR ROOT
long long sqrt(long long x)
{
long long s = 0, e = 2e9, res = s;
while (s <= e)
{
long long m = (s + e) / 2;
if (m * m <= x)
res = m, s = m + 1;
else
e = m - 1;
}
return res;
}
////////////////////////////////////////////////////////// BINOMIAL COEFF
vl fact(2e5 + 5, 1);
ll binPow(ll a, ll b)
{
if (b == 0)
return 1;
if (b == 1)
return a;
ll ret = binPow(a, b / 2);
if (b % 2 == 0)
return (ret * ret) % mod;
return ((ret * ret) % mod * a) % mod;
}
ll inv(ll a)
{
return (binPow(a, mod - 2) % mod + mod) % mod;
}
ll binom(ll a, ll b)
{
if (b < 0 or a < 0)
return 0;
return (((fact[a] * inv(fact[b])) % mod * inv(fact[a - b])) % mod + mod) % mod;
}
/*
vi a(n);
for(int i=0; i<n; i++){
cin>>a[i];
}
*/
#define no cout << "NO\n"
#define yes cout << "YES\n"
/*----------------------------------------------------------------------------*/
void solve()
{
int n;
cin >> n;
if (odd(n))
{
cout << n - 9 << sp << 9;
}
else
{
cout << n - 8 << sp << 8 << nl;
}
}
/*
*/
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
int t = 1;
while (t--)
solve();
}