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state.cpp
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119 lines (113 loc) · 6.59 KB
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//作者：蒋明君
#include "all.h"
void state_update()
{
num_iscompleting = 0;
num_isovertiming = 0;
memset(num_completing, -1, sizeof(num_completing));
memset(num_overtiming, -1, sizeof(num_overtiming));
for (int i = 0; i < num_deliver_man; i++)
{
for (int k = 0; k < deliver_man[i].num_mission / 2; k++)
{
if ((time - deliver_man[i].task[k].order_time >= 60) && (deliver_man[i].task[k].is_complete != 1))
{
is_break = 1;
break;
}
}
if (is_break == 1)
break;
if (deliver_man[i].index_misson > deep_dsf - 2)
order_dispose(i);
deliver_man[i].stopflag1 = 0;
deliver_man[i].stopflag2 = 0;
if (deliver_man[i].num_mission == 0 || deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].is_complete == 1)//如果这个订单已经被完成跳过这一单
continue;
int aim_x = (deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].fetch_time == 0 ? deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].x_start : deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].x_terminal);//决定这是一个取单还是送单，确定其x坐标
int aim_y = (deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].fetch_time == 0 ? deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].y_start : deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].y_terminal);//决定这是一个取单还是送单，确定其y坐标
int arrive = 0;
if (abs(deliver_man[i].x_location - aim_x) + abs(deliver_man[i].y_location - aim_y) == 1)//第1种情况，这个订单刚好就在快递员附近
{
arrive = 1;//标记订单到达
}
else if (deliver_man[i].x_location == 0 || deliver_man[i].x_location == 16)//修正坐标到边角的情况，此时订单没有直接到达，需要一个倒车来校正方向
{
deliver_man[i].x_location == 0 ? deliver_man[i].x_location += 2 : deliver_man[i].x_location -= 2;
}
else if (deliver_man[i].y_location == 0 || deliver_man[i].y_location == 16)//修正坐标到边角的情况，此时订单没有直接到达，需要一个倒车来校正方向
{
deliver_man[i].y_location == 0 ? deliver_man[i].y_location += 2 : deliver_man[i].y_location -= 2;
}
else if (abs(deliver_man[i].x_location - aim_x) == 1 || abs(deliver_man[i].y_location - aim_y) == 1)//第2种情况，取单和送单在一条街上，后面的情况要转化成现在的情况，通过一个转向的操作
{
if (abs(deliver_man[i].x_location - aim_x) == 1)//x方向上快递员与目标点同向，改变y坐标逼近目标点
deliver_man[i].y_location > aim_y ? deliver_man[i].y_location -= 2 : deliver_man[i].y_location += 2;
else if (abs(deliver_man[i].y_location - aim_y) == 1)//y方向上快递员与目标点同向，改变x坐标逼近目标点
deliver_man[i].x_location > aim_x ? deliver_man[i].x_location -= 2 : deliver_man[i].x_location += 2;
if (abs(deliver_man[i].x_location - aim_x) + abs(deliver_man[i].y_location - aim_y) == 1)//若操作完成后订单到达，标记arrive
arrive = 1;//标记订单到达
}
else if (abs(deliver_man[i].x_location - aim_x) <= 2 || abs(deliver_man[i].y_location - aim_y) <= 2)//第3种情况，快递员需要转向来逼近目的地
{
deliver_man[i].x_location >= aim_x ? deliver_man[i].x_location-- : deliver_man[i].x_location++;
deliver_man[i].y_location >= aim_y ? deliver_man[i].y_location-- : deliver_man[i].y_location++;
}
else //第4种情况，快递员无需转向或者直接接近，先逼近坐标
{
if (deliver_man[i].x_location % 2 == 0)
deliver_man[i].x_location >= aim_x ? deliver_man[i].x_location -= 2 : deliver_man[i].x_location += 2;
else
deliver_man[i].y_location >= aim_y ? deliver_man[i].y_location -= 2 : deliver_man[i].y_location += 2;
}
if (arrive == 1)//如果订单被送到了
{
while (abs(deliver_man[i].x_location - aim_x) + abs(deliver_man[i].y_location - aim_y) == 1)//为了防止相同的时间点有多个任务
{
int temp = ++put_matrix[aim_x][aim_y].count;//这个点的任务数量自加
put_matrix[aim_x][aim_y].deliver_man_i[temp] = i;//记录快递员是谁
put_matrix[aim_x][aim_y].is_done[temp] = (deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].fetch_time == 0 ? 0 : 1);//记录是取单还是送单
put_matrix[aim_x][aim_y].num_deliver[temp] = deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].number;//记录订单编号
if (deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].fetch_time == 0)//一个取单操作完成
{
deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].fetch_time = 1;
}
else//送单操作完成
{
deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].is_complete = 1;
if (time - deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].order_time < dead_line)//订单在规定时间被送达
{
num_completing[num_iscompleting] = deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].number;
num_iscompleting++;
money += 10;
deliver_music = 1;
num_completed++;
num_iscompleting++;
}
else if (time - deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].order_time >= dead_line && time - deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].order_time <= total_dead_line)//订单超时但不至破产
{
num_overtiming[num_isovertiming] = deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].number;
num_isovertiming++;
money -= 40;
num_overtime++;
warn_music = 1;//播放超时提醒
}
else//破产结算
{
num_overtime++;
is_break = 1;
warn_music = 1;//播放超时提醒
}
}
deliver_man[i].num_mission--, deliver_man[i].index_misson++;//任务数减1，任务指针加1
if (deliver_man[i].num_mission == 0 || deliver_man[i].mission_queue[deliver_man[i].index_misson] == -1 || deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].is_complete == 1)//若有好几个订单起始和终止相同，不判定这个时候的任务数量会出错
break;
aim_x = (deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].fetch_time == 0 ? deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].x_start : deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].x_terminal);//更新下一个坐标，观察是否是一个地点有好几个任务
aim_y = (deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].fetch_time == 0 ? deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].y_start : deliver_man[i].task[deliver_man[i].mission_queue[deliver_man[i].index_misson]].y_terminal);
}
}
add_deliver();
if (money < 0)
is_break = 1; //若钱数<0，则破产
}
}