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LCS DP Problem
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76 lines (63 loc) · 1.31 KB
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#include <iostream>
using namespace std;
int lcs_mem(string s, string t, int **output) {
int m = s.size();
int n = t.size();
// Base case
if(s.size() == 0 || t.size() == 0) {
return 0;
}
// Check if ans already exists
if(output[m][n] != -1) {
return output[m][n];
}
int ans;
// Recursive calls
if(s[0] == t[0]) {
ans = 1 + lcs_mem(s.substr(1), t.substr(1), output);
}
else {
int a = lcs_mem(s.substr(1), t, output);
int b = lcs_mem(s, t.substr(1), output);
int c = lcs_mem(s.substr(1), t.substr(1), output);
ans = max(a, max(b, c));
}
// Save your calculation
output[m][n] = ans;
// Return ans
return ans;
}
int lcs_mem(string s, string t) {
int m = s.size();
int n = t.size();
int **output = new int*[m+1];
for(int i = 0; i <= m; i++) {
output[i] = new int[n+1];
for(int j = 0; j <= n; j++) {
output[i][j] = -1;
}
}
return lcs_mem(s, t, output);
}
int lcs(string s, string t) {
// Base case
if(s.size() == 0 || t.size() == 0) {
return 0;
}
// Recursive calls
if(s[0] == t[0]) {
return 1 + lcs(s.substr(1), t.substr(1));
}
else {
int a = lcs(s.substr(1), t);
int b = lcs(s, t.substr(1));
int c = lcs(s.substr(1), t.substr(1));
return max(a, max(b, c));
}
}
int main() {
string s, t;
cin >> s >> t;
cout << lcs_mem(s, t) << endl;
cout << lcs(s, t) << endl;
}