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@Amaan-29
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@super30admin
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Strengths:

  • The solution correctly implements the backtracking approach to generate all unique combinations.
  • The code is clean and well-organized, with clear separation of base cases and logic.
  • The use of backtracking (adding and then removing) is efficient and avoids creating multiple list copies.

Areas for Improvement:

  • Consider renaming the variable "set" to something more descriptive like "currentCombination" or "path", as it is a list that represents the current combination being built. The term "set" might be confusing because it implies no duplicates, but here duplicates are allowed.
  • You can optimize slightly by checking if target - candidates[idx] >= 0 before making the recursive call for the "choose" case. This would prevent the function from being called when the target becomes negative, reducing the number of recursive calls. However, the current solution is correct without it.

Example of the optimized call:

if (target - candidates[idx] >= 0) {
    set.add(candidates[idx]);
    helper(candidates, target - candidates[idx], idx, result, set);
    set.remove(set.size()-1);
}

But note that the base condition already checks for target < 0, so it is optional.

Overall, excellent job! The solution is efficient and correct.

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2 participants