2problems completed

[BharathVuppala96]

No description provided.

[super30admin]

Your solution for the subsets problem is correct and efficient. Well done! Here are a few points to consider:

1. The use of path+[nums[i]] in the recursive call for the choose branch is a clean way to avoid mutation and backtracking manually. However, be aware that it creates a new list each time, which has a cost in terms of memory and time. For larger inputs (though the constraints are small here), this might be less efficient than using a single list and backtracking with append and pop. But given the constraints, it is acceptable.
2. The base case appends the path directly without making a copy in the no-choose branch? Actually, in the no-choose branch, you pass the same list reference. However, since you are not modifying the list in the no-choose branch and you create a new list in the choose branch, it works correctly. But note that in the base case, you append path (which is the same reference) without copying. This could lead to issues if you later modify the path. However, in your implementation, since you never modify the list after passing it (and in the choose branch you create a new list), it is safe. But to be consistent and avoid potential bugs, you might consider appending a copy in the base case. However, in your code, the base case is reached only when i==len(nums), and at that point, the path is not modified again. So it is correct as is.
3. The code is clean and easy to understand. Good job on following the recursive structure.

For the subsets problem, your solution is correct. However, I noticed you also included a solution for "Palindrome partitioning" in the same response. Please make sure to only submit the relevant code for the problem you are solving.